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A bag contains 5 white, 6 red and 4 green balls. One ball is drawn at random. What is the probability that the ball drawn is 

(i) green?

(ii) white? 

(iii) non-red?

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(i). 

Total number of balls bag containing is: 5 white + 6 red + 4 green = 15 balls 

Number of green balls = 4.

Probability (P) = \(\frac{Number\,of\,favorable\,outcomes}{Total\,number\,of\,outcomes}\)

∴ Probability of getting a Green ball P(G)

\(\frac{Number\,of\,Green\,balls}{Total\,number\,of\,balls}\) = \(\frac{4}{15}\)

(ii). 

Total number of balls bag containing is: 5 white + 6 red + 4 green = 15 balls 

Number of white balls = 5.

Probability (P) = \(\frac{Number\,of\,favorable\,outcomes}{Total\,number\,of\,outcomes}\)

∴ Probability of getting a white ball P(W)

\(\frac{Number\,of\,White\,balls}{Total\,number\,of\,balls}\) = \(\frac{5}{15}=\frac{1}{3}\)

(iii). 

Total number of balls bag containing is: 5 white + 6 red + 4 green = 15 balls 

Number of outcomes (No Red) = 5 + 4 = 9, that is 5 white balls + 4 Green balls.

Probability (P) = \(\frac{Number\,of\,favorable\,outcomes}{Total\,number\,of\,outcomes}\)

∴ Probability of getting a Green ball P(G)

\(\frac{Number\,of\,blue+White\,balls}{Total\,number\,of\,balls}\) = \(\frac{9}{15}=\frac{3}{5}\)

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