Question

Construct a ∆ABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.

Answer 1

Steps of construction: 

Step 1: Draw a line segment BC of 3.5 cm 

Step 2: At B, draw an angle XBC of 45^o

Step 3: With center B and radius 1.5 cm draw an arc which intersects BX at D. 

Step 4: Join DC 

Step 5: Draw the perpendicular bisector of DC which intersects BD produced at A. 

Step 6: Join AC 

∆ABC is the required triangle