Correct answer is (c) (8n - 2)
Let Sn denotes the sum of first n terms of the AP.
∴ Sn = 4n2 + 2n
\(\Rightarrow\) Sn-1 = 4(n - 1)2 + 2(n - 1)
= 4(n2 - 2n + 1) + 2(n - 1)
∴ nth term of the AP, an = Sn - Sn-1
= (4n2 + 2n) - (4n2 - 6n + 2)
= 8n - 2
Thus, the nth term of thee AP is (8n - 2)