Correct answer is (b) 15
We know that the radius and tangent are perpendicular at their point of contact
In right triangle AOB
By using Pythagoras theorem, we have
OA2 = AB2 + OB2
\(\Rightarrow\) 172 = AB2 + OB2
\(\Rightarrow\) 289 = AB2 + 64
\(\Rightarrow\) AB2 = 225
\(\Rightarrow\) AB = 15 cm
The tangents drawn from the external point are equal
Therefore, the length of AC is 15 cm