Given: equation is 3x − 2y + 6 = 0
Concept Used:
Line in intercepts form is \(\frac{x}{a}+\frac{y}{b}=1\) ( a and b are x and y intercepts resp.)
Explanation:
3x − 2y = - 6
\(\frac{3}{-6}x+\frac{2y}{6}=1\) [Dividing both sides by - 6]
\(\frac{x}{-2}+\frac{y}{3}=1\)
Thus, the intercept form of the given line
∴ x - intercept = −2 and y - intercept = 3
