Correct answer is A. 1
Let say GP is a,ar,ar2
where a is the first term and r is the common ratio
Also, given that r = 2
So, GP becomes
a,2a,4a nth term = ar (n-1) = 128
a. 2(n-1) = 128

⇒ a.2n = 256
Sum of n terms of GP

Substituting a 2n in above equation we get
-255 = a-256
a =1.