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Show that the perpendicular bisectors of the sides of a triangle are concurrent.

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To prove: 

Perpendicular bisectors of the sides of a triangle are concurrent. 

Assuming: 

ABC be a triangle with vertices A (x1, y1), B (x2, y2) and C (x3, y3). 

Let D, E and F be the midpoints of the sides BC, CA and AB, respectively. 

Explanation: 

Thus, the coordinates of D, E and F are

Let mD, mE and mF be the slopes of AD, BE and CF respectively. 

∴ Slope of BC × mD = -1

⇒ \(\frac{y_2-y_2}{x_2-x_2}\)  x mD = -1

⇒mD = \(-\frac{x_2-x_2}{y_2-y_2}\) 

Thus, the equation of AD

Let L1, L2 and L3 represent the lines (1), (2) and (3), respectively. Adding all the three lines, 

We observe: 1 ⋅ L1 + 1⋅L2 + 1⋅L3 = 0 

Hence proved, the perpendicular bisectors of the sides of a triangle are concurrent.

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