Let OA be the lighthouse and B and C be the positions of the ship.
Thus, we have:
OA = 100m, \(\angle OBA\) = 30° and \(\angle OCA\) = 60°
![](https://www.sarthaks.com/?qa=blob&qa_blobid=3089218948226041741)
Let
OC = xm and BC = ym
In the right \(\triangle OAC\), we have
![](https://www.sarthaks.com/?qa=blob&qa_blobid=4347074053728375706)
∴ Distance travelled by the ship during the period of observation = B = y = 115.47m