Given:
4x + 3y − 7 = 0 … (1)
8x + 5y − 1 = 0 … (2)
The equation of the line with slope – 3/2 is given below:
y = - 32x + c
⇒ 32x + y - c = 0 … (3)
The lines (1), (2) and (3) are concurrent.
⇒ 8c = 8
⇒ c = 1
On substituting c = 1 in = \(-\frac{3}{2}x+c\), we get:
y = \(-\frac{3}{2}x+1\)
⇒ 3x + 2y – 2 = 0
