First of all we should convert the given velocity into proper units, that is, we should convert the velocity of 36 kilometres per hour into metres per second (because the time is given in seconds). ltBrgt Now, `" "` 1km = 1000 m
So, `" "` 36 km = 36 `xx` 1000 m
`" "` = 36,000 m `" "` ...(1)
Also, `" "` 1 hour = 60 minutes
`" "` = 60 `xx` 60 seconds
`" "` = 3600 s `" "` ...(2)
So, `" "` 36 km per hour = `(36,000" m")/(3600" s")` ltBrgt `" "` = 10 m/s `" "` ...(3)
Thus, the given velocity of 36 km per hour is equal to 10 metres per second.
Now, `" "` Initial velocity, `u` = 0 (Scooter starts from rest)
`" "` Final velocity, `v` = 10 m/s (Calculated above)
`" "` Acceleration, `a` = ? (To be calculated)
And, `" "` Time, `t` = 10 s
Thus, the acceleration is 1 m/`s^(2)`.
