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A man does 200 J of work in 10s and a boy does 100 J of work in 4s. (a) who is delivering more power? (b) Find the ratio of the power delivered by the man to that delivered by the boy.

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Correct Answer - A::B::D
(a) Power delivered by the man, `P_1 =(200J)/(10s) = 20W`
Power delivered by the boy, `P_2 = (100J)/(4s) = 25W`
Thus, the boy delivers more power.
(b) `(P_1)/(P_2) =(20)/(25) 4//5`

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