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Usha swims in a `90 m` long pool. She covers `180 m` in one minute by swimming from one end to the other and back along the same length path. Find the average speed and average speed and average velocity of Usha.

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Correct Answer - `3 ms^(-1)` ; zero
Here , total distance travelled , ` s = 180 m` , time taken , `t = 1 min. = 60s`
Average speed `= (s)/(t) = ( 180)/( 60) = 3 m//s`
In swimming from one end to the other and back along the same straight path , displacement `= 0`.
Average velocity `= ("displacement")/("time") = zero`

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