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If \(f(x) = \begin{cases} 2x+3 ,x≤{0}\\ 3(x+1), x>{ 0} \end{cases} \). Find \(\lim\limits_{x \to 0}\) f(x) and \(\lim\limits_{x \to 1}\) f(x).

f(x) = {2x+3, x ≤ 0 3(x+1),x < 0

lim f(x), x∈3 and lim f(x), x∈1

1 Answer

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Best answer

Given,

f(x) = {2x+3, x ≤ 0 3(x+1),x < 0

(i)To find : lim f(x), x∈0 

To limit to exist, we know

Thus to find the limit using the concept,

From above equations,

Thus the limit exists.

Thus from (5),

\(\lim\limits_{x \to 0}\) f(x) = 3

(ii) To find : lim f(x), x∈1

To limit to exist, we know

Thus to find the limit using the concept,

From above equations,

\(\lim\limits_{x \to 1^+}\) f(x) = \(\lim\limits_{x \to 1^-}\)f(x)

Thus from (2),(3) and (4),

\(\lim\limits_{x \to 1}\) f(x) = 5

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