Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.7k views
in Ellipse by (29.0k points)
closed by

Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:

4x2 + y2 - 8x + 2y + 1 = 0

1 Answer

+1 vote
by (29.9k points)
selected by
 
Best answer

Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse

4x2 + y2 - 8x + 2y + 1 = 0.

⇒ 4x2 + y2 - 8x + 2y + 1 = 0

⇒ 4(x2 - 2x + 1) + (y2 + 2y + 1) - 4 = 0

⇒ 4(x - 1)2 + (y + 1)2 = 4

Comparing with the standard form

⇒ Centre = (p, q) = (1, - 1)

Here b> a2

⇒ eccentricity(e) =

Length of the major axis 2b = 2(2) = 4

Length of the minor axis 2a = 2(1) = 2

⇒ Foci = (p, q ± be)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...