Given: (1 – i)2 (1 + i) – (3 – 4i)2
= (1 + i2 – 2i)(1 + i) – (9 + 16i2 – 24i)
[∵(a – b)2 = a2 + b2 – 2ab]
= (1 – 1 – 2i)(1 + i) – (9 – 16 – 24i) [∵ i2 = -1]
= (-2i)(1 + i) – (- 7 – 24i)
Now, we open the brackets
- 2i × 1 – 2i × i + 7 + 24i
= - 2i – 2i2 + 7 + 24i
= - 2(-1) + 7 + 22i [∵, i2 = -1]
= 2 + 7 + 22i
= 9 + 22i