Given: (-3 + 5i)3 We know that,
(-a + b)3 = - a3 + 3a2b – 3ab2 + b3 …(i)
So, on replacing a by 3 and b by 5i in eq. (i), we get
-(3)3 + 3(3)2 (5i) – 3(3)(5i)2 + (5i)3
= -27 + 3(9)(5i) – 3(3)(25i2) + 125i3
= -27 + 135i – 225i2 + 125i3
= -27 + 135i – 225 × (-1) + 125i × i2
= -27 + 135i + 225 – 125i [∵ i2 = -1]
= 198 + 10i
