Question

ABCD is a rectangle whose three vertices are A(4,0), C(4,3) and D(0,3). Find the length of one its diagonal.

Answer 1

 The given vertices are B(4,0), C(4,3) and D(0,3) Here, BD one of the diagonals So

BD = \(\sqrt{(4-0)^2+(0-3)^2}\)

= \(\sqrt{(4^2)+(-3)^2}\)

= \(\sqrt{16+9}\)

= \(\sqrt{25}\)

= 5

Hence, the length of the diagonal is 5 units.