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In each of the following find the equations of the hyperbola satisfying the given conditions foci(0 \(\pm\)√10) , passing through (2, 3)

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Given: Foci (0 \(\pm \sqrt{10}\)) passing through (2, 3) 

To find: equation of the hyperbola 

Formula used: 

The standard form of the equation of the hyperbola is,

\(\frac{x^2}{a^2} - \frac{y^2}{b^2}\) = -1

Coordinates of the foci for a standard hyperbola is given by (0, ±be) 

According to the question:

be = \(\sqrt{10}\)

⇒ b2e2 = 10

Since (2, 3) passing through hyperbola 

\(\frac{x^2}{a^2} - \frac{y^2}{b^2}\) = -1

Therefore,

{∵ a2 = b2(e2 – 1)}

⇒ 90 – 13b2 = (10 – b2)b2 

⇒ 90 – 13b2 = 10b2 – b4 

⇒ 90 – 13b2 – 10b2 + b4 = 0 

⇒ b4 – 23b2 + 90 = 0 

⇒ b4 – 18b2 – 5b2 + 90 = 0 

⇒ b2(b2 – 18) – 5(b2 – 18) = 0 

⇒ (b2 – 18)(b2 – 5) = 0 

⇒ b2 = 18 or 5 

Case 1: 

b2 = 18 and b2e2 = 10 

a2 = b2(e2 – 1) 

⇒ a2 = b2e2 – b2 

⇒ a2 = 10 – 18 

⇒ a2 = – 8 

Hence, equation of hyperbola is:

Case 2: 

b2 = 5 and b2e2 = 10 

a2 = b2(e2 – 1) 

⇒ a2 = b2e2 – b2 

⇒ a2 = 10 – 5 

⇒ a2 = 5

Hence, equation of hyperbola is:

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