If 1/6! + 1/7! = x/8! find the value of x.

Question

If \(\frac{1}{6!}+\frac{1}{7!}=\frac{x}{8!}\) find the value of x.

Answer 1

Given Equation : 

\(\frac{1}{6!}+\frac{1}{7!}=\frac{x}{8!}\)

To Find : Value of x.

Formula : n! = n x (n-1)!

By given equation,

\(\frac{1}{6!}+\frac{1}{7!}=\frac{x}{8!}\) 

Cancelling (8!) from both the sides, 

∴x = 64 

Conclusion : Value of x is 64.