
Since the form is indeterminant
\(=\cfrac00\)
Method 1: factorization
\(\lim\limits_{\text x \to 2}\cfrac{\text x^3+3\text x^2-9\text x-2}{\text x^3 - \text x-6} \)
By long division method

Since a3 - b3 = (a - b) (a2 + b2 + ab) & a2 - b2 = (a + b) (a - b)

Method2: By L hospital rule:
Differentiating numerator and denominator separately:
