Given:

Adding 2 to both sides in the above equation

Signs of 4x – 3:
4x – 3 = 0 → x = \(\cfrac{3}{4}\)
(Adding 3 to both sides and then dividing both sides by 4)
4x – 3 > 0 → x > \(\cfrac{3}{4}\)
(Adding 3 to both sides and then dividing both sides by 4)
4x – 3 > 0 → x < \(\cfrac{3}{4}\)
(Adding 3 to both sides and then dividing both sides by 4)
Signs of x – 1:
x – 1 = 0 → x = 1 (Adding 1 to both the sides)
x – 1 > 0 → x > 1 (Adding 1 to both the sides)
x – 1 < 0 → x < 1 (Adding 1 to both the sides)
At x = 1 \(\frac{4{\text{x}} - 3}{{\text{x}}-1}\) is not defined.
Intervals that satisfy the required condition: > 0

Subtracting 2 from both the sides

Signs of x – 1:
x – 1 = 0 → x = 1 (Adding 1 on both the sides)
x – 1 < 0 → x < 1 (Adding 1 on both the sides)
x – 1 > 0 → x > 1 (Adding 1 on both the sides)
At x = 1 \(\frac{1}{{\text{x}} - 1}\) is not defined
Interval which satisfy the required condition: < 0
x < 1
Now, combining the intervals:
x < \(\cfrac{3}{4}\) or x > 1 and x <1
Merging the overlapping intervals:
x < \(\cfrac{3}{4}\)
Therefore,
x ∈ (-∞, \(\frac{3}{4}\))