We have 3x – 5 < x + 7
⇒ 3x < x + 12 (Adding 5 to both sides)
⇒ 2x < 12 (Subtracting x from both sides)
⇒ x < 6 (Dividing by 2 on both sides)
(i) Solution set is {1, 2, 3, 4, 5}
(ii) Solution set is {0, 1, 2, 3, 4, 5}
(iii) Solution set is {....– 3, – 2, –1, 0, 1, 2, 3, 4, 5}
(iv) Solution set is {x : x ∈ R and x < 6}, i.e., any real number less than 6.