|x| < 4 Square
⇒ x2 < 16
⇒ x2 – 16 < 0
⇒ x2 – 42 < 0
⇒ (x + 4)(x – 4) < 0
Observe that when x is greater than 4, (x + 4)(x – 4) is positive
And for each root the sign changes hence

We want less than 0 that is negative part
Hence x should be between -4 and 4 for (x + 4)(x – 4) to be negative
Hence x ∈ (-4, 4)
Hence the solution set of |x| < 4 is (-4, 4)