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We have |3– 4x| ≥9.

⇒ 3 – 4x ≤ – 9 or 3 – 4x ≥ 9 (Since |x| ≥ a⇒ x ≤ – a or x ≥ a)

⇒ – 4x ≤ – 12 or – 4x ≥ 6

⇒ x ≥ 3 or x ≤ -3/2 (Dividing both sides by – 4)

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