Question

While measuring the diameter of a sphere with a vernier callipers M.S.R and V.S.D. are 35 mm and 5 respectively . If the vernier scale coinciding with 19 division of main scale what is the diameter of the sphere?

Answer 1

M.S.R =35 mm
V.S.D=5
Diameter of the sphere = M.S.R + V.S.D`xx` L.C.
Given that 20 division of the vernier scale is equal to 19 division of the main scale
L.C. =1 M.S.D`//` no of division on V.S. =1 mm `//` 20 =0.5mm
Total reading =M.S.R + n`xx`L.C. =35 mm + `5xx 0.05` mm=35.25 mm