Question

Two electrones each of mass `9.1xx10^(31)` kg are at a distance of 10 A. calculate the gravitational force of attraction between them. Given `1 A=10^(10) m`.

Answer 1

Correct Answer - `5.52 xx 10^(53)N`
Here, `m_(1)=m_(2)=9.1xx10^(-31) kg, r=10 A=10 xx 10^(-10) m=10^(-9)m, G=6.67xx10^(-11) Nm^(2)//kg^(2), F=?`
Thus, `F=(Gm_(1)m_(2))/r^(2)=(6.67xx10^(-11)xx(9.1xx10^(31))^(2))/((10^(-9))^(2))=5.52xx10^(53)N`