(i) Use the definition of mechanical advantage and principle of moments.
(ii) Calculate the effort (E) required to pull the load, using E = mg ` sin theta`.
(iii) Part of the total force required to pull the load is provided by 100 kgwt.
(iv) Calculate the remaining force by ` E - (100 xx 10) N = F_(1)`.
(v) `F_(1)xxR` forms anti-clockwise moment on the pulley, where R = radius of the pulley.
(vi) Let `F_(2)` be the force forming a couple so that the load is just raised.
(vii) Calculate `F_(2)` using : `F_(1)xx R=F_(2)xx2(R)`.
(viii) 1000 N.