Prove `cot theta+tan theta=(cosec theta)(sec theta)` by completing the following activity: LHS`=cot theta+tan theta` `=(cos theta)/(sin theta)+(square)/(cos theta)` `=(square +square)/(sin thetaxx co cos theta)` `=(square)/(sin thetaxx cos theta)` `=1/(square)xx1/(square)` `=cosec thetaxx sec theta` `=RHS` `:.cot theta+tan theta=cosec thetaxx sec theta`