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If `sinA=9/(41)` , compute `cosA` and `tanA` .

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If `sinA=9/(41)` , compute `cosA` and `tanA` .
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Correct Answer - `cos A =(40)/(41), tan A=(9)/(40)`
`sin A=(9)/(41)=(BC)/(AC).`
` therefore AB^(2)=AC^(2)-(41)^(2)-(9)^(2)=1681-81=1600`
` therefore cos A =(AB)/(AC)=(40)/(41) and tan A =(BC)/(AB)=(9)/(40).`
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