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Find `.^(n)C_(3)`, if `.^(n)C_(7)=.^(n)C_(4)`.

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Find `.^(n)C_(3)`, if `.^(n)C_(7)=.^(n)C_(4)`.
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`.^(n)C_(7)=.^(n)C_(4)rArrn=7+4=11`
So `.^(n)C_(3)=.^(11)C_(3)=(11xx10xx9)/(1xx2xx3)=165`.
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`.^(n)C_(3)`=___
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