Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
110 views
in Geometric Progressions by (51.0k points)
closed by

Construct a quadratic in x such that A.M. of its roots is A and G.M. is G.

1 Answer

+1 vote
by (49.4k points)
selected by
 
Best answer

Let the root of the quadratic equation be a and b.

According to the given condition,

⇒ AM = a+b/2 = A

⇒ a + b = 2A …..(1)

⇒ GM = √ab = G

= ab = G2…(2)

The quadratic equation is given by,

x2– x (Sum of roots) + (Product of roots) = 0

x2 – x (2A) + (G2) = 0

x2 – 2Ax + G2 = 0 [Using (1) and (2)]

Thus, the required quadratic equation is x2 – 2Ax + G2 = 0.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...