Question

Find the area of quadrilateral ABCD in which

AB = 42cm, BC = 21cm, CD = 29cm, DA = 34 cm and diagram BD + 20cm.

Answer 1

Quadrilateral ABCD is divided into triangles \(\triangle ABD\) and \(\triangle BCD.\)

We will now use Hero’s formula

For \(\triangle ABD\,:\)

For \(\triangle BCD \,:\)

Thus, we have:

Area of quadrilatera ABCD = Ar(\(\triangle ABD\)) + Ar(BDC) = 336 + 210 = 546 cm²