Given: sin θ = \(\frac{-1}{2}\)

Since, θ is in IVth Quadrant. So, sin and tan will be negative but cos will be positive.
We know that,
sin2 θ + cos2 θ = 1
Putting the values, we get

Since, θ in IVth quadrant and cosθ is positive in IVth quadrant
∴ cos θ = \(\frac{\sqrt{3}}2{}\)
Now,

Now,

= \(-\sqrt{3}\)
Hence, the values of other trigonometric Functions are:
