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If A + B + C = π, prove that

sin A + sin B + sin C = 4cos \(\frac{A}2\) cos\(\frac{B}2\)cos\(\frac{C}2\)

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Best answer

sin A + sin B + sin C 

Using,

Since A + B + C = π 

→ B + C = 180 - A

And,

Using, sin2A = 2sinAcosA

→ B + C = 180 - A

And,

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