(i) Given: cos 5x/2 = 0
Formula used: cos θ = 0
⇒ θ = (2n + 1) π/2, n ∈ l
By using the above formula, we have
(ii) Given: cos(x + π/10) = 0
Formula used: cos θ = 0
⇒ θ = (2n + 1) π/2, n ∈ l
By using the above formula, we have
so general solution is x = nπ + 2π/5 where n ∈ l
(iii) Given: tan 2x = 0
Formula used: tan θ = 0
⇒ θ = nπ, n ∈ l
By using the above formula, we have
tan 2x = 0
⇒ 2x = nπ
⇒ x = nπ/2 where n ∈ l
(iv) Given: tan (3x + π/6) = 0
Formula used: tan θ = 0
⇒ θ = nπ, n ∈ l
By using the above formula, we have
(v) Given: tan(2x - π/4) = 0
Formula used: tan θ = 0
⇒ θ = nπ, n ∈ l
By using the above formula, we have
