
= 2sin 9x cos 2x
Using,
sin(A + B) = sinA cosB + cosA sinB

= 2cos\(\frac{10x}{2}sin\frac{4x}{2}\)
= 2cos5x sin2x
Using,
sin( A - B)= sinA cos B - cosA sinB

= \(2cos\frac{12x}{2}cos\frac{2x}{2}\)
= 2cos 6x cosx
Using,
cos (A + B) = cosAcosB - sinAsinB

= -2sin\(\frac{6x}{2}\)sin\(\frac{-2x}{2}\)
= 2sin3x sinx
Using,
cos (A - B) = cosAcosB + sinAsinB