\(\lim\limits_{\text x \to0}\cfrac{2\,sin\,\text x-sin\,2\text x}{\text x^3} \)
lim(x→0) (2 sin x - sin 2x)/x3
To Find: Limits
NOTE: First Check the form of imit. Used this method if the limit is satisfying any one from 7 indeterminate form.
In this Case, indeterminate Form is \(\cfrac00\)
We know that sin 2x = 2 sin x cos x
Formula used : \(\lim\limits_{\text x \to 0}\cfrac{1-cos\,\text x}{\text x^2}=\cfrac12\) and \(\lim\limits_{\text x \to 0}\cfrac{sin\,\text x}{\text x}=1\)
So, by using the above formula, we have
