Condition (1):
Since, f(x) = e-x sin x is a combination of exponential and trigonometric function which is continuous.
⇒ f(x) = e-x sin x is continuous on [0, π].
Condition (2):
Here, f’(x) = e-x (cos x – sin x) which exist in [0,π].
So, f(x) = e-x sin x is differentiable on (0,π)
Condition (3):
Here, f(0) = e-0 sin0 = 0
And f(π) = e-πsinπ = 0
i.e. f(0) = f(π)
Conditions of Rolle’s theorem are satisfied.
Hence, there exist at least one cϵ(0,π) such that f’(c) = 0
i.e. e-c (cos c – sin c) = 0
i.e. cos c - sin c = 0
i.e. c = π/4
Value of c = π/4 ∈ (0, π)
Thus, Rolle’s theorem is satisfied.