Question

Let y = y(x) be the solution of the differential equation cosec²xdy+2dx = (1+y cos2x) cosec²xdx, with y(π/4) = 0. Then, the value of (y(0) + 1)² is equal to :

(1) e^1/2

(2) e^–1/2

(3) e^–1

(4) e

Answer 1

Answer is: (3) e^-1

Given