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Evaluate: \(\int\cfrac{x^2}{(x^2+6x-3)}dx\)

∫ x2/(x2+6x-3)dx

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To find:\(\int\cfrac{x^2}{(x^2+6x-3)}dx\)

Formula Used:

Given equation can be rewritten as following:

Using partial fractions,

6x – 3 = A (2x + 6) + B 

Equating the coefficients of x, 

6 = 2A 

A = 3 

Also, -3 = 6A + B 

⇒ B = -21 

Substituting in (1),

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