Given : A = \(\begin{bmatrix} 1 & 2 \\[0.3em] 3& 4 \\[0.3em] \end{bmatrix}\), B = \(\begin{bmatrix} 2& 0 \\[0.3em] 1& -3 \\[0.3em] \end{bmatrix}\) and C = \(\begin{bmatrix} 1&-1 \\[0.3em] 0& 1 \\[0.3em] \end{bmatrix}.\)
Matrix A is of order 2 x 2 , matrix B is of order 2 x 2 and matrix C is of order 2 x 2
To verify : A(B + C) = (AB + AC)
Formula used :

Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
If A is a matrix of order a b and B is a matrix of order c x d ,then matrix AB exists and is of order a x d ,
if and only if b = c
If A is a matrix of order a b and B is a matrix of order c x d ,then matrix BA exists and is of order c x b ,
if and only if d = a

Matrix A(B + C) is of order 2 x 2

For matrix AB, a = b = c = d = 2 ,matrix AB is of order 2 x 2

A(B + C) = \(\begin{bmatrix}
5 & -5 \\[0.3em]
13 & -11 \\[0.3em]
\end{bmatrix}\)
For matrix AB, a = b = c = d = 2 ,matrix AB is of order 2 x 2

For matrix AC, a = b = c = d = 2 ,matrix AC is of order 2 x 2


A(B + C) = (AB + AC)