Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+2 votes
8.2k views
in Mathematics by (15.9k points)

If \(\displaystyle \int_0^{\pi}\)(sin3 x)e-sin^2x dx = α - \(\frac{\beta}{e}\) \(\displaystyle \int^1_0 \sqrt{t} e^t dt\), then \(\alpha + \beta\) is equal to ...... .

∫(sin^3x)esin^2x dx  x ∈ [0, π]= α - β/e ∫√t et dt x ∈ [0,1] ​ ​

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...