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∫ cos 3x dx = ?

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Mark (√) against the correct answer of the following:

 ∫ cos 3x dx = ?

A. \(-\frac{1}{3}\text{sin}\,3x + C\)

B. \(\frac{1}{3}\text{sin}\,3x + C\)

C. 3 sin 3x + C

D. -3 sin 3x + C

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1 Answer

+1 vote
by (47.5k points)
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Best answer

Correct answer is B.

Given =  ∫ cos 3x

So, ∫ cos 3x dx = \(\frac{sin\,3x}{3}+c\)

where c is the integrating constant.

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