(a The number of the edges= The number fo sides of the base `xx3=3xx3=9.`
(b) The volume of the prism`=`Area fo the base`xx` Height of the prism`=(1)/(2)(3xx4)xx7=42m^(3)`.
(c ) `TSA=LSA+2`(Area of base)
`=ph+2`(Area of base)
where, p = Perimeter of the base = sum of lengths of the sides of the given triangle.
As, hypotenuse of the triangle `sqrt(3^(2)+4^(2))=sqrt(25)=5m`
`implies LSA=ph=12xx7=84 m^(2).`