Find the general solution of the following differential equation: = dy/dx = 3e^{2x}+ 3d^{4x}/e^x + e^{-x}

Question

Find the general solution of the following differential equation:

\(\frac{dy}{dx}\) = \(\frac{3e^{2x}+3d^{4x}}{e^x+e^{-x}}\)

dy/dx = 3e^2x + 3d^4x/e^x + e^-x

Answer 1

\(\frac{dy}{dx}\) = \(\frac{3e^{2x}+3d^{4x}}{e^x+e^{-x}}\)

\(\frac{dy}{dx}\) = \(\frac{3e^{2x}+3d^{4x}}{e^x+\frac{1}{e^x}}\)

Integrating on both the sides,