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If y = \(\sqrt{\frac{sec\,x-1}{sec\,x+1}}\) then dy/dx = ?

√(sec x-1/sec x+1)

A. sec2x

B. 1/2 sec2 x/2

C. -1/2 cosec2 x/2

D. none of these

1 Answer

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Answer is: B. 1/2 sec2 x/2

Given that y = \(\sqrt{\frac{sec\,x-1}{sec\,x+1}}\)

Multiplying by cos x in numerator and denominator, we get

Differentiating with respect to x, we get

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