Area of rectangle `=40xx30 cm^(2) = 1200 cm^(2)`
Area of circle `=pi(10)^(2)=100pi cm^(2)`
`therefore" Area of remaining protion "= (1200-100pi) cm^(2)`
`therefore" Required probability "=("Favourable portion")/("Total portion")=(100(12-pi))/(1200)`
`=(12-(22)/(7))/(12)=(84-22)/(7xx12)=(62)/(7xx12)=(31)/(42)`
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/161132201314121240340ZDkAa3pAAKWAD9r.png)