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A metallic hemisphere is melted and recast in the shape of a cone with the same base radius R as that of the hemisphere. If `H` is the height of the cone, then write the value of `H//Rdot`

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Note the volume will remain the same.
volume of hemisphere=`2/3pir^3`
volume of cone=`1/3pir^2h`
`1/3pir^2h=2/3pir^3`
=>`h/r=2/1`

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