Let us take C = AB

LHS = C’
\(\Rightarrow\) \(
\begin{bmatrix}
4 & -4 \\[0.3em]
6&-21 \\[0.3em]
\end{bmatrix}\)
A' = \(
\begin{bmatrix}
-1 & 4 \\[0.3em]
2&-21 \\[0.3em]
-3 &6
\end{bmatrix}\)
And B' = \(
\begin{bmatrix}
3 & 2 &-1 \\[0.3em]
-4&-1 &0 \\[0.3em]
-4 &1&0
\end{bmatrix}\)
RHS = B’A’

LHS = RHS
Hence proved.