Question

`Delta ABC` is right-angled at A and `AD bot BC`. If `BC=13 cm and AC=5 cm`, find the ratio of areas of `Delta ABC and Delta ADC`.

Answer 1

Correct Answer - `169:25`
In `Delta BAC and Delta ADC`, we have
`angle BAC= angle ADC=90^(@)`
`and angle ACB= angle DCA= angle C`
`:. Delta BAC~Delta ADC`. [ by AA-similarity]
`:. (ar (Delta ABC))/(ar (Delta ADC))=(ar (DeltaBAC))/(ar (Delta ADC))=(BC^(2))/(AC^(2))`